{"id":1120,"date":"2025-11-06T09:06:36","date_gmt":"2025-11-06T09:06:36","guid":{"rendered":"https:\/\/blog.ngocha.biz\/?p=1120"},"modified":"2026-05-27T18:22:31","modified_gmt":"2026-05-27T18:22:31","slug":"dai-bollinger","status":"publish","type":"post","link":"https:\/\/blog.ngocha.biz\/?p=1120","title":{"rendered":"D\u1ea3i Bollinger"},"content":{"rendered":"
\n \n<\/presto-player>\n<\/figure>\n<\/p><\/div>\n

D\u1ea3i Bollinger l\u00e0 m\u1ed9t ch\u1ec9 b\u00e1o k\u1ebft h\u1ee3p gi\u1eefa xu h\u01b0\u1edbng v\u00e0 dao \u0111\u1ed9ng. N\u00f3 \u0111\u01b0\u1ee3c d\u00f9ng c\u1ef1c k\u1ef3 ph\u1ed5 bi\u1ebfn; h\u1ea7u nh\u01b0 n\u0111t n\u00e0o c\u0169ng s\u1eed d\u1ee5ng. Trong entry n\u00e0y ta \u0111i s\u00e2u v\u00e0o hi\u1ec3u b\u1ea3n ch\u1ea5t c\u1ee7a d\u1ea3i Bollinger \u0111\u1ec3 c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng cho \u0111\u00fang.<\/p>\n

Ph\u00eda d\u01b0\u1edbi l\u00e0 cp VCG v\u1edbi hai d\u1ea3i Bollinger Band. M\u1ed9t d\u1ea3i c\u00f3 \u0111\u1ed9 l\u1ec7ch chu\u1ea9n = 1 (g\u1ecdi t\u1eaft l\u00e0 BB1) v\u00e0 m\u1ed9t d\u1ea3i c\u00f3 \u0111\u1ed9 l\u1ec7ch chu\u1ea9n =2 (g\u1ecdi t\u1eaft l\u00e0 BB2). Ta th\u1ea5y gi\u00e1 m\u1ed7i khi \u0111i t\u1edbi \u0111\u01b0\u1eddng bi\u00ean tr\u00ean, d\u01b0\u1edbi v\u00e0 gi\u1eefa lu\u00f4n c\u00f3 nh\u1eefng ph\u1ea3n \u1ee9ng nh\u1ea5t \u0111\u1ecbnh. Khi gi\u00e1 \u0111\u1eadp bi\u00ean tr\u00ean c\u1ee7a BB2 n\u00f3 c\u00f3 xu h\u01b0\u1edbng gi\u1ea3m tr\u1edf l\u1ea1i ch\u1ea1m v\u00e0o bi\u00ean tr\u00ean c\u1ee7a BB1. <\/p>\n

Trong m\u1ed9t xu h\u01b0\u1edbng t\u0103ng khi ch\u1ea1m v\u00e0o bi\u00ean tr\u00ean BB1 x\u00e1c su\u1ea5t n\u00f3 quay tr\u1edf l\u1ea1i bi\u00ean tr\u00ean BB2 cao h\u01a1n so v\u1edbi vi\u1ec7c xuy\u00ean qua \u0111\u1ec3 ch\u1ea1m \u0111\u01b0\u1eddng gi\u1eefa MA20. T\u1ea1i \u0111\u01b0\u1eddng gi\u1eefa n\u00f3 c\u0169ng c\u00f3 ph\u1ea3n \u1ee9ng t\u01b0\u01a1ng t\u1ef1 l\u00e0 t\u0103ng tr\u1edf l\u1ea1i. Nh\u01b0ng khi xuy\u00ean qua n\u00f3 l\u1ea1i \u0111i ti\u1ebfp t\u1edbi BB1 v\u00e0 c\u0169ng c\u00f3 nh\u1eefng ph\u1ea3n \u1ee9ng t\u01b0\u01a1ng t\u1ef1.<\/p>\n

T\u00f3m l\u1ea1i \u0111\u1ec3 n\u00f3 t\u1eeb bi\u00ean tr\u00ean c\u1ee7a BB2 t\u1edbi bi\u00ean d\u01b0\u1edbi c\u1ee7a BB2 l\u1ea7n l\u01b0\u1ee3t n\u00f3 ph\u1ea3i qua \u0111\u01b0\u1ee3c c\u00e1c h\u1ed7 tr\u1ee3 l\u00e0 d\u1ea3i tr\u00ean BB1, \u0111\u01b0\u1eddng gi\u1eefa, d\u1ea3i d\u01b0\u1edbi BB1. V\u00e0 khi khi \u0111i l\u00ean t\u1eeb d\u1ea3i d\u01b0\u1edbi n\u00f3 c\u0169ng ph\u1ea3i qua t\u1eebng \u0111\u00f3 c\u00e1c kh\u00e1ng c\u1ef1.<\/p>\n

\"\"<\/figure>\n

Khi ch\u00fang ta ra c\u00e1c quy\u1ebft \u0111\u1ecbnh mua hay b\u00e1n b\u1ea3n ch\u1ea5t l\u00e0 ch\u00fang ta \u0111ang tham gia v\u00e0o m\u1ed9t b\u00e0i to\u00e1n x\u00e1c su\u1ea5t. Ch\u00fang ta tham gia v\u00e0o c\u00e1c v\u00e1n c\u01b0\u1ee3c m\u00e0 x\u00e1c su\u1ea5t th\u1eafng c\u00e0ng cao c\u00e0ng t\u1ed1t v\u00e0 tr\u00e1nh xa c\u00e1c deal c\u00f3 x\u00e1c su\u1ea5t thua cao. <\/p>\n

V\u00ec v\u1eady hi\u1ec3u m\u1ed9t ch\u00fat v\u1ec1 x\u00e1c su\u1ea5t th\u1ed1ng k\u00ea c\u0169ng t\u1ed1t. Ph\u00eda d\u01b0\u1edbi l\u00e0 ph\u1ed5 \u0111i\u1ec3m thi ti\u1ebfng anh 2025:<\/p>\n

\"\"<\/figure>\n

Tr\u1ee5c tung l\u00e0 s\u1ed1 l\u01b0\u1ee3ng h\u1ecdc sinh, tr\u1ee5c ho\u00e0nh l\u00e0 \u0111i\u1ec3m thi (t\u1eeb 0 t\u1edbi 10). \u0110i\u1ec3m trung b\u00ecnh l\u00e0 5,38; \u0111\u01b0\u1ee3c t\u00ednh b\u1eb1ng c\u00e1ch c\u1ed9ng to\u00e0n b\u1ed9 \u0111i\u1ec3m c\u1ee7a th\u00ed sinh l\u1ea1i r\u1ed3i chia cho s\u1ed1 l\u01b0\u1ee3ng th\u00ed sinh. Trung v\u1ecb b\u1eb1ng 5,25 c\u00f3 ngh\u0129a l\u00e0 50% th\u00ed sinh c\u00f3 \u0111i\u1ec3m nh\u1ecf h\u01a1n 5,25 v\u00e0 50% c\u00f3 \u0111i\u1ec3m l\u1edbn h\u01a1n 5,25. \u0110i\u1ec3m (5-5,25) c\u00f3 c\u1ed9t cao nh\u1ea5t v\u1edbi 24.463 th\u00ed sinh.<\/p>\n

Trung v\u1ecb 5,25 kh\u00f4ng ph\u1ea3i c\u1ed9t cao nh\u1ea5t, n\u00f3 l\u00e0 \u0111i\u1ec3m ph\u00e2n t\u00e1ch gi\u1eefa 50% th\u1ea5p h\u01a1n v\u00e0 50% cao h\u01a1n; chia \u0111\u00f4i s\u1ed1 l\u01b0\u1ee3ng th\u00ed sinh. Trung v\u1ecb, trung b\u00ecnh, c\u1ed9t cao nh\u1ea5t c\u00f3 c\u00e1ch t\u00ednh ho\u00e0n to\u00e0n kh\u00e1c nhau nh\u01b0ng \u1edf \u0111\u00e2y g\u1ea7n s\u00e1t nhau th\u1ec3 hi\u1ec7n ph\u1ed5 \u0111i\u1ec3m r\u1ea5t c\u00e2n \u0111\u1ed1i. <\/p>\n

\u0110\u1ed9 l\u1ec7ch chu\u1ea9n = 1,45 c\u00f3 ngh\u0129a l\u00e0:<\/strong><\/p>\n

    \n
  • C\u00f3 68,2% th\u00ed sinh n\u1eb1m trong kho\u1ea3ng 1 \u0111\u1ed9 l\u1ec7ch chu\u1ea9n: t\u1eeb 5,38-1,45 t\u1edbi 5,38+1,45 = t\u1eeb 3,93 t\u1edbi 6,83 \u0111i\u1ec3m.<\/li>\n
  • C\u00f3 95,4% th\u00ed sinh n\u1eb1m trong kho\u1ea3ng 2 \u0111\u1ed9 l\u1ec7ch chu\u1ea9n: 5,38 – 2 x 1,45 t\u1edbi 5,38 +2 x 1,45 = t\u1eeb 2,48 t\u1edbi 8,28 \u0111i\u1ec3m<\/li>\n<\/ul>\n

    Quay tr\u1edf l\u1ea1i ch\u1ec9 b\u00e1o Bollinger Band. \u0110\u1ed9 l\u1ec7ch chu\u1ea9n = 1 c\u00f3 ngh\u0129a l\u00e0 c\u00f3 68,2% gi\u00e1 n\u1eb1m trong d\u1ea3i BB1 v\u00e0 95,4% gi\u00e1 n\u1eb1m d\u1ea3i BB2. V\u1eady khi gi\u00e1 ch\u1ea1m v\u00e0o bi\u00ean BB1 th\u00ec c\u00f3 68,2% kh\u1ea3 n\u0103ng n\u00f3 quay tr\u1edf l\u1ea1i v\u00e0 c\u00f3 31,8% kh\u1ea3 n\u0103ng n\u00f3 xuy\u00ean qua. Khi g\u1eb7p bi\u00ean BB2 c\u00f3 95,4% kh\u1ea3 n\u0103ng n\u00f3 quay tr\u1edf l\u1ea1i v\u00e0o trong v\u00e0 ch\u1ec9 c\u00f3 4,6% kh\u1ea3 n\u0103ng n\u00f3 xuy\u00ean qua.<\/p>\n

    V\u1eady \u0111\u1ed9 l\u1ec7ch chu\u1ea9n trong Bollinger Band \u0111\u01b0\u1ee3c t\u00ednh nh\u01b0 th\u1ebf n\u00e0o? v\u00ed d\u1ee5 cho VCG \u1edf tr\u00ean<\/p>\n

      \n
    • \u0110\u01b0\u1eddng gi\u1eefa l\u00e0 MA20; l\u00e0 trung b\u00ecnh \u0111\u01a1n gi\u1ea3n c\u1ee7a 20 phi\u00ean = 26,3. <\/li>\n
    • Bi\u00ean tr\u00ean c\u1ee7a BB1 = 27,47<\/li>\n
    • Bi\u00ean d\u01b0\u1edbi c\u1ee7a BB1 = 25,16<\/li>\n<\/ul>\n

      \u0110\u1ed9 l\u1ec7ch chu\u1ea9n = 1,17. C\u00f3 ngh\u0129a l\u00e0 th\u1ed1ng k\u00ea 20 phi\u00ean g\u1ea7n nh\u1ea5t: Gi\u00e1 trung b\u00ecnh l\u00e0 26,3 v\u1edbi \u0111\u1ed9 l\u1ec7ch chu\u1ea9n =1,17. C\u00f3 68,2% l\u1ea7n gi\u00e1 \u0111\u00f3ng c\u1eeda trong kho\u1ea3ng t\u1eeb 25,16 t\u1edbi 27,47. BB2 v\u1edbi x\u00e1c su\u1ea5t 95,4% l\u00e0 nh\u00e2n 2 c\u1ee7a \u0111\u1ed9 l\u1ec7ch chu\u1ea9n. <\/p>\n

      \u0110\u1ed9 l\u1ec7ch chu\u1ea9n c\u00e0ng l\u1edbn th\u00ec d\u1ea3i c\u00e0ng r\u1ed9ng v\u00e0 \u0111\u1ed9 l\u1ec7ch chu\u1ea9n c\u00e0ng b\u00e9 th\u00ec d\u1ea3i c\u00e0ng h\u1eb9p.<\/p>\n

      V\u1eady c\u00f3 ph\u1ea3i l\u00e0 c\u1ee9 \u0111\u1eadp bi\u00ean tr\u00ean th\u00ec b\u00e1n v\u00e0 \u0111\u1eadp bi\u00ean d\u01b0\u1edbi th\u00ec mua?<\/strong><\/p>\n

      C\u00e2u tr\u1ea3 l\u1eddi l\u00e0 kh\u00f4ng ph\u1ea3i<\/strong> v\u00ec th\u1ed1ng k\u00ea c\u1ee7a 20 phi\u00ean kh\u00f4ng th\u1ec3 \u0111\u1ea1i di\u1ec7n cho di\u1ec5n bi\u1ebfn gi\u00e1 c\u1ee7a cp v\u1ed1n di\u1ec5n ra t\u1eeb r\u1ea5t l\u00e2u trong qu\u00e1 kh\u1ee9 \u0111\u01b0\u1ee3c. N\u00f3 gi\u1ed1ng nh\u01b0 vi\u1ec7c b\u1ea1n theo d\u00f5i h\u00e0nh vi c\u1ee7a m\u1ed9t ng\u01b0\u1eddi trong 20 ng\u00e0y v\u00e0 d\u1ef1 \u0111o\u00e1n h\u00e0nh vi c\u1ee7a anh ta trong t\u01b0\u01a1ng lai. R\u00f5 r\u00e0ng anh ta \u0111\u00e3 sinh ra r\u1ea5t l\u00e2u tr\u01b0\u1edbc \u0111\u00e2y v\u00e0 20 ng\u00e0y qua c\u00f3 th\u1ec3 c\u00f3 m\u1ed9t \u0111\u1eb7c th\u00f9 n\u00e0o \u0111\u00f3 kh\u00f4ng gi\u1ed1ng nh\u01b0 b\u00ecnh th\u01b0\u1eddng. <\/p>\n

      M\u1ed9t c\u1ed5 phi\u1ebfu \u0111ang trong xu h\u01b0\u1edbng t\u0103ng c\u00f3 th\u1ec3 li\u00ean t\u1ee5c m\u1edf r\u1ed9ng bi\u00ean tr\u00ean c\u0169ng nh\u01b0 m\u1ed9t cp \u0111ang xu h\u01b0\u1edbng gi\u1ea3m c\u00f3 th\u1ec3 li\u00ean t\u1ee5c k\u00e9o r\u1ed9ng bi\u00ean d\u01b0\u1edbi. Khi cp v\u01b0\u1ee3t bi\u00ean tr\u00ean n\u00f3 kh\u00f4ng ph\u1ea3i v\u00f9ng qu\u00e1 mua n\u00f3 ch\u1ec9 th\u1ec3 hi\u1ec7n r\u1eb1ng cp \u0111ang m\u1ea1nh c\u0169ng nh\u01b0 khi n\u00f3 xuy\u00ean bi\u00ean d\u01b0\u1edbi c\u0169ng kh\u00f4ng ph\u1ea3i v\u00f9ng qu\u00e1 b\u00e1n, n\u00f3 ch\u1ec9 c\u00f3 \u00fd ngh\u0129a r\u1eb1ng cp \u0111ang y\u1ebfu.<\/p>\n

      C\u0169ng nh\u01b0 c\u00e1c ch\u1ec9 b\u00e1o kh\u00e1c b\u1ea1n s\u1ebd c\u1ea7n ph\u1ea3i k\u1ebft h\u1ee3p m\u1ed9t v\u00e0i ch\u1ec9 b\u00e1o \u0111\u1ec3 c\u00f3 th\u1ec3 c\u00f3 quy\u1ebft \u0111\u1ecbnh \u0111\u00fang.<\/p>\n

      \u0110\u1ed9 r\u1ed9ng c\u1ee7a Bollinger Band<\/mark><\/strong><\/p>\n

      \u0110\u1ed9 r\u1ed9ng c\u1ee7a BB= (Gi\u00e1 tr\u1ecb d\u1ea3i tr\u00ean – Gi\u00e1 tr\u1ecb d\u1ea3i d\u01b0\u1edbi)\/gi\u00e1 tr\u1ecb \u0111\u01b0\u1eddng gi\u1eefa.<\/p>\n

      \u1ede v\u00ed d\u1ee5 VCG \u1edf tr\u00ean \u0111\u1ed9 r\u1ed9ng BB2 = (28,64 – 24,06)\/26,27 = 4,58\/26,27 = 0,17<\/p>\n

      \"\"<\/figure>\n

      Vi\u1ec7c t\u00ednh \u0111\u1ed9 r\u1ed9ng Bollinger Band c\u00f3 \u00fd ngh\u0129a khi so s\u00e1nh gi\u1eefa c\u00e1c cp kh\u00e1c nhau v\u00ec v\u1edbi c\u00f9ng m\u1ee9c bi\u1ebfn \u0111\u1ed9ng 1000 \u0111\u1ed3ng th\u00ec cp c\u00f3 gi\u00e1 10.000\u0111 s\u1ebd kh\u00e1c v\u1edbi m\u1ed9t cp \u0111ang c\u00f3 gi\u00e1 100.000\u0111. Khi quan s\u00e1t ri\u00eang l\u1ebb m\u1ed9t cp ta ch\u1ec9 c\u1ea7n so s\u00e1nh b\u1eb1ng m\u1eaft l\u00e0 c\u00f3 th\u1ec3 nh\u1eadn ra d\u1ea3i \u0111ang m\u1edf r\u1ed9ng hay co h\u1eb9p.<\/p>\n

      V\u00ed d\u1ee5 v\u1edbi cp VCG \u1edf tr\u00ean ta th\u1ea5y gi\u00e1 \u0111ang d\u01b0\u1edbi MA20 v\u00e0 MA20 \u0111ang d\u1ed1c xu\u1ed1ng th\u1ec3 hi\u1ec7n cp trong trung h\u1ea1n l\u00e0 \u0111i xu\u1ed1ng. D\u1ea3i \u0111ang trong xu th\u1ebf m\u1edf r\u1ed9ng th\u1ec3 hi\u1ec7n gi\u00e1 v\u1eabn \u0111ang c\u00f3 xu h\u01b0\u1edbng \u0111i xu\u1ed1ng.<\/p>\n

      Ch\u00fang ta c\u00f3 th\u1ec3 d\u00f9ng ch\u1ec9 b\u00e1o BBW \u0111\u1ec3 \u0111o m\u1ee9c \u0111\u1ed9 m\u1edf r\u1ed9ng hay co h\u1eb9p c\u1ee7a BB.<\/p>\n

      %B c\u1ee7a Bollinger Band<\/mark><\/strong><\/p>\n

      %B = (Gi\u00e1 hi\u1ec7n t\u1ea1i – gi\u00e1 tr\u1ecb d\u1ea3i d\u01b0\u1edbi)\/(Gi\u00e1 tr\u1ecb d\u1ea3i tr\u00ean – Gi\u00e1 tr\u1ecb d\u1ea3i d\u01b0\u1edbi). <\/p>\n

      Gi\u00e1 hi\u1ec7n t\u1ea1i l\u00e0 gi\u00e1 \u0111\u00f3ng c\u1eeda n\u1ebfu \u0111\u00e3 k\u1ebft th\u00fac phi\u00ean giao d\u1ecbch trong ng\u00e0y.<\/em><\/p>\n

      Nh\u01b0 v\u1eady %B th\u1ec3 hi\u1ec7n v\u1ecb tr\u00ed c\u1ee7a gi\u00e1 hi\u1ec7n t\u1ea1i trong d\u1ea3i BB. N\u1ebfu coi d\u1ea3i l\u00e0 m\u1ed9t b\u00ecnh x\u0103ng th\u00ec %B l\u00e0 m\u1ee9c c\u1ee7a b\u00ecnh x\u0103ng. N\u00f3 t\u01b0\u01a1ng t\u1ef1 nh\u01b0 vi\u1ec7c t\u00ednh %K trong ch\u1ec9 b\u00e1o Stochastic.<\/p>\n

      %B = ( 14.700 – 13.200)\/(14.900-13.200) = 1.500\/1.700 = 0,88<\/p>\n

      \"\"<\/figure>\n

      \u00c1p d\u1ee5ng %B s\u1ebd t\u01b0\u01a1ng t\u1ef1 nh\u01b0 \u00e1p d\u1ee5ng %K. <\/p>\n

      Giao d\u1ecbch v\u1edbi Bollinger Band<\/mark><\/strong><\/p>\n

      1. Chuy\u1ec3n t\u1eeb co h\u1eb9p sang m\u1edf r\u1ed9ng<\/em><\/strong><\/p>\n

      \"\"<\/figure>\n

      Khi %B c\u1eaft l\u00ean 1 l\u00e0 n\u00f3 ph\u00e1 bi\u00ean tr\u00ean v\u00e0 c\u1eaft xu\u1ed1ng 0 l\u00e0 n\u00f3 ph\u00e1 bi\u00ean d\u01b0\u1edbi. B\u1eb1ng m\u1eaft th\u01b0\u1eddng ta c\u00f3 th\u1ec3 th\u1ea5y t\u1ea1i \u0111i\u1ec3m A tr\u01b0\u1edbc \u0111\u00f3 cp \u0111ang b\u1ecb co h\u1eb9p sau \u0111\u00f3 n\u00f3 break l\u00ean v\u1edbi m\u1ed9t phi\u00ean kh\u1ed1i l\u01b0\u1ee3ng g\u1ea5p 5 l\u1ea7n kh\u1ed1i l\u01b0\u1ee3ng phi\u00ean tr\u01b0\u1edbc \u0111\u00f3; sau \u0111\u00f3 d\u1ea3i m\u1edf r\u1ed9ng. %B li\u00ean ti\u1ebfp tr\u00ean m\u1ee9c 50% cho khi n\u00f3 xuy\u00ean qua 50% v\u00e0 \u0111\u00e2m xu\u1ed1ng bi\u00ean 0 ph\u00eda d\u01b0\u1edbi. T\u1eeb \u0111\u00f3 MA20 h\u01b0\u1edbng xu\u1ed1ng th\u1ec3 hi\u1ec7n cp \u0111\u00e3 chuy\u1ec3n t\u1eeb xu h\u01b0\u1edbng t\u0103ng sang xu h\u01b0\u1edbng gi\u1ea3m.<\/p>\n

      Nh\u00ecn ch\u1ec9 b\u00e1o BBW th\u00ec khi cp h\u01b0\u1edbng l\u00ean c\u00f3 ngh\u0129a n\u00f3 \u0111ang m\u1edf r\u1ed9ng; tr\u01b0\u1edbc \u0111\u00f3 n\u00f3 c\u00f3 th\u1ec3 \u0111i ngang ho\u1eb7c t\u1eeb ph\u00eda tr\u00ean \u0111\u00e2m xu\u1ed1ng nh\u01b0 v\u00ed d\u1ee5. V\u1edbi m\u1ed9t kh\u1ed1i l\u01b0\u1ee3ng giao d\u1ecbch l\u1edbn t\u1ea1i \u0111i\u1ec3m n\u00e0y th\u00ec \u0111\u00f3 l\u00e0 d\u1ea5u hi\u1ec7u r\u1ea5t t\u1ed1t \u0111\u1ec3 mua ho\u1eb7c cho v\u00e0o danh s\u00e1ch theo d\u00f5i ch\u1edd mua.<\/p>\n

      M\u1ed9t cp \u0111ang b\u1ecb co h\u1eb9p th\u1ec3 hi\u1ec7n n\u00f3 \u0111ang \u0111\u01b0\u1ee3c t\u00edch l\u0169y. Giai \u0111o\u1ea1n t\u00edch l\u0169y nh\u01b0 ch\u00fang ta bi\u1ebft c\u00f3 th\u1ec3 k\u00e9o d\u00e0i v\u00e0i ng\u00e0y, v\u00e0i tu\u1ea7n th\u1eadm ch\u00ed v\u00e0i th\u00e1ng ho\u1eb7c c\u1ea3 n\u0103m. N\u1ebfu \u0111\u00e1nh theo tr\u01b0\u1eddng ph\u00e1i break th\u00ec ta s\u1ebd mua ngay trong phi\u00ean Break ho\u1eb7c \u0111\u1ee3i cp \u0111\u1eadp l\u1ea1i h\u1ed7 tr\u1ee3 (m\u00e0 tr\u01b0\u1edbc \u0111\u00f3 l\u00e0 c\u1ea3n) th\u00ec mua.<\/p>\n

      T\u1ea1i th\u1eddi \u0111i\u1ec3m hi\u1ec7n t\u1ea1i 5\/11. CP \u0111\u00e3 ch\u1ea1m bi\u00ean tr\u00ean v\u00e0 MA20 \u0111\u00e3 b\u1eaft \u0111\u1ea7u b\u1ecb b\u1ebb ngang. CP \u0111\u00e3 c\u00f3 d\u1ea5u hi\u1ec7u l\u1ea5y l\u1ea1i \u0111\u01b0\u1ee3c xu h\u01b0\u1edbng t\u0103ng. <\/p>\n

      Ph\u00eda d\u01b0\u1edbi l\u00e0 \u0111\u1ed3 th\u1ecb c\u1ee7a Novaland:<\/p>\n

      T\u1ea1i th\u1eddi \u0111i\u1ec3m A cp \u0111ang dao \u0111\u1ecdng quanh bi\u00ean c\u1ee7a BB1 v\u00e0 MA20 th\u00ec c\u00f3 m\u1ed9t c\u00fa break l\u00ean v\u1edbi thanh kho\u1ea3n g\u1ea5p 2,5 l\u1ea7n phi\u00ean tr\u01b0\u1edbc \u0111\u00f3. Ai mua theo tr\u01b0\u1eddng ph\u1ea3i break s\u1ebd mua t\u1ea1i phi\u00ean n\u00e0y. Sau \u0111\u00f3 cp li\u00ean t\u1ee5c gi\u1eef \u0111\u01b0\u1ee3c tr\u00ean bi\u00ean tr\u00ean c\u1ee7a BB1 v\u00e0 khi n\u00f3 ph\u00e1 v\u1ee1 BB1 th\u00ec n\u00f3 \u0111\u00e2m xuy\u00ean qua MA20, bi\u00ean d\u01b0\u1edbi c\u1ee7a BB1 v\u00e0 BB2. V\u1ec1 nguy\u00ean t\u1eafc ch\u00fang ta ph\u1ea3i b\u00e1n khi h\u1ed7 tr\u1ee3 c\u1ee7a cp b\u1ecb ph\u00e1 v\u1ee1. N\u1ebfu ph\u00e1 v\u1ee1 gi\u1ea3 th\u00ec cp ph\u1ea3i quay tr\u1edf l\u1ea1i tr\u00ean h\u1ed7 tr\u1ee3 trong v\u00f2ng 2 phi\u00ean \u0111\u1eb1ng n\u00e0y n\u00f3 li\u00ean ti\u1ebfp ph\u00e1 v\u1ee1 th\u1ec3 hi\u1ec7n xu th\u1ebf \u0111\u00e3 \u0111\u1ed5i chi\u1ec1u.<\/p>\n

      \"\"<\/figure>\n

      T\u1edbi th\u1eddi \u0111i\u1ec3m B th\u00ec c\u00f3 v\u1ebb hi\u1ec7n tr\u1ea1ng g\u1ea7n gi\u1ed1ng A nh\u01b0ng n\u00f3 l\u1ea1i l\u00e0 m\u1ed9t c\u00fa l\u1eeba khi ngay phi\u00ean h\u00f4m sau \u0111\u00e3 \u0111\u00e2m th\u1ee7ng li\u00ean ti\u1ebfp. V\u00ec v\u1eady kh\u00f4ng ph\u1ea3i c\u1ee9 break l\u00ean l\u00e0 cp v\u00e0o xu h\u01b0\u1edbng t\u0103ng, v\u1eabn la b\u00e0i to\u00e1n x\u00e1c su\u1ea5t; v\u1eabn c\u00f3 % th\u1eadt b\u1ea1i v\u00ec v\u1eady \u0111\u1eb7t d\u1eebng l\u1ed7 ph\u1ea3i ngay d\u01b0\u1edbi MA20.<\/p>\n

      2. T\u00f4n tr\u1ecdng c\u00e1c h\u1ed7 tr\u1ee3\/kh\u00e1ng c\u1ef1 c\u1ee7a BB1 v\u00e0 BB2<\/strong><\/p>\n

      B\u1ea1n c\u00f3 th\u1ec3 m\u1edf b\u1ea5t k\u1ef3 m\u1ed9t cp n\u00e0o c\u0169ng s\u1ebd th\u1ea5y trong m\u1ed9t xu th\u1ebf t\u0103ng cp s\u1ebd lu\u00f4n \u1edf bi\u00ean tr\u00ean b\u00e1m s\u00e1t kho\u1ea3ng gi\u1eefa bi\u00ean tr\u00ean BB1 v\u00e0 BB2; th\u1ec9nh tho\u1ea3ng n\u00f3 n\u00f3 s\u1ebd test MA20 nh\u01b0ng s\u1ebd nhanh ch\u00f3ng b\u1eadt l\u00ean. N\u1ebfu n\u00f3 ph\u00e1 v\u1ee1 MA20 th\u00ec trong v\u00f2ng 2 phi\u00ean kh\u00f4ng quay tr\u1edf l\u1ea1i th\u00ec n\u00f3 s\u1ebd \u0111\u1eadp xu\u1ed1ng bi\u00ean d\u01b0\u1edbi v\u00e0 khi \u1edf d\u01b0\u1edbi MA20 n\u00f3 c\u0169ng ph\u1ea3i m\u1ea5t c\u01a1 s\u1ed1 phi\u00ean d\u01b0\u1edbi MA20; c\u00f3 th\u1ec3 l\u00e3i c\u1ee7a b\u1ea1n mua tr\u01b0\u1edbc \u0111\u00f3 \u0111\u00e3 m\u1ea5t r\u1ed3i; v\u00ec v\u1eady c\u1ea7n c\u00e2n nh\u1eafc b\u00e1n khi ph\u00e1 v\u1ee1 MA20. \u0110\u00e2y l\u00e0 t\u00f4i ch\u1ec9 x\u00e9t ri\u00eang ch\u1ec9 b\u00e1o BB; c\u00f2n th\u01b0\u1eddng b\u1ea1n s\u1ebd ph\u1ea3i d\u00f9ng th\u00eam v\u00e0i ch\u1ec9 b\u00e1o kh\u00e1c \u0111\u1ec3 c\u1ee7ng c\u1ed1 cho quy\u1ebft \u0111\u1ecbnh b\u00e1n ho\u1eb7c gi\u1eef.<\/p>\n

      Khi m\u1ed9t cp b\u00e1m v\u00e0o d\u1ea3i tr\u00ean c\u1ee7a BB2 v\u00e0 t\u00f4n tr\u1ecdng d\u1ea3i tr\u00ean c\u1ee7a BB1 nh\u01b0 m\u1ed9t h\u1ed7 tr\u1ee3 th\u00ec ch\u1ee9ng t\u1ecf cp \u0111ang r\u1ea5t kh\u1ecfe; th\u1eadm ch\u00ed ta c\u00f3 th\u1ec3 mua th\u00eam khi n\u00f3 ch\u1ea1m BB1. Khi cp b\u00e1m v\u00e0o d\u1ea3i d\u01b0\u1edbi c\u1ee7a BB2; khi h\u1ed3i l\u00ean n\u00f3 kh\u00f4ng ph\u00e1 v\u1ee1 n\u1ed5i d\u1ea3i d\u01b0\u1edbi c\u1ee7a BB1 th\u00ec xu th\u1ebf gi\u1ea3m ch\u01b0a ch\u1ea5m d\u1ee9t; ta kh\u00f4ng \u0111\u01b0\u1ee3c mua. Mu\u1ed1n thay \u0111\u1ed5i xu h\u01b0\u1edbng tr\u01b0\u1edbc h\u1ebft n\u00f3 ph\u1ea3i ph\u00e1 v\u1ee1 d\u01b0\u1ee3c c\u1ea3n d\u01b0\u1edbi BB1; sau \u0111\u00f3 ti\u1ebfp t\u1ee5c ph\u00e1 v\u1ee1 MA20 \u0111\u1ec3 l\u00ean v\u00f9ng tr\u00ean MA20.<\/p>\n

      Phia d\u01b0\u1edbi l\u00e0 \u0111\u1ed3 th\u1ecb c\u1ee7a ng\u00e2n h\u00e0ng MB. T\u1ea1i A Bb co h\u1eb9p v\u00e0 m\u1edf r\u1ed9ng sau \u0111\u00f3 gi\u00e1 b\u00e1m r\u1ea5t s\u00e1t d\u1ea3i tr\u00ean BB2; khi ph\u00e1 v\u1ee1 d\u1ea3i tr\u00ean BB1 n\u00f3 kh\u00f4ng v\u01b0\u1ee3t l\u1ea1i \u0111\u01b0\u1ee3c v\u00e0 ph\u00e1 ti\u1ebfp MA20. T\u1ea1i th\u1eddi \u0111i\u1ec3m B c\u00f3 v\u1ebb m\u1ecdi th\u1ee9 gi\u1ed1ng v\u1edbi A nh\u01b0ng l\u1ea7n n\u00e0y n\u00f3 break xuy\u00ean qua bi\u00ean d\u01b0\u1edbi BB2. CP hi\u1ec7n qu\u00e1 y\u1ebfu kh\u00f4ng v\u01b0\u1ee3t n\u1ed5i d\u1ea3i d\u01b0\u1edbi c\u1ee7a BB1.<\/p>\n

      \"\"<\/figure>\n

      Vi\u1ec7c ph\u00e2n t\u00edch k\u1ef9 thu\u1eadt \u0111\u00f2i h\u1ecfi b\u1ea1n ph\u1ea3i nh\u00ecn r\u1ea5t r\u1ed9ng c\u1ea3 m\u1ed9t qu\u00e1 tr\u00ecnh c\u1ee7a cp thay v\u00ec nh\u00ecn gi\u00e1 trong ng\u00e0y. C\u00f3 ng\u01b0\u1eddi nh\u00ecn gi\u00e1 trong ng\u00e0y r\u1ed3i ra quy\u1ebft \u0111\u1ecbnh mua b\u00e1n ngay; th\u1ea5y \u0111\u1ecf th\u00ec mua th\u1ea5y xanh th\u00ec b\u00e1n. L\u00e0m nh\u01b0 v\u1eady ch\u1ec9 d\u00e0nh cho d\u00e2n trader chuy\u00ean nghi\u1ec7p. Ng\u01b0\u1eddi kh\u00f4ng chuy\u00ean v\u00e0 c\u0169ng kh\u00f4ng c\u00f3 th\u1eddi gian b\u00e1m b\u1ea3ng li\u00ean t\u1ee5c n\u00ean nh\u00ecn d\u00e0i ra. \u0110\u01a1n gi\u1ea3n m\u1ed9t cp trong 100 phi\u00ean t\u1eeb gi\u00e1 7000\u0111 l\u00ean gi\u00e1 14.000\u0111 c\u00f3 th\u1ec3 tr\u1ea3i qua 95 phi\u00ean \u0111i ngang ho\u1eb7c gi\u1ea3m; 5 phi\u00ean c\u00f2n l\u1ea1i th\u00ec t\u0103ng. C\u00e0ng b\u00e1m b\u1ea3ng b\u1ea1n c\u00e0ng kh\u00f4ng th\u1ec3 gi\u1eef \u0111\u01b0\u1ee3c cp.<\/p>\n

      Gi\u00e1 \u0111\u00f3ng c\u1eeda:<\/strong><\/p>\n

      Gi\u00e1 \u0111\u00f3ng c\u1eeda \u0111\u00f3ng vai tr\u00f2 c\u1ef1c k\u1ef3 quan tr\u1ecdng v\u00ec n\u00f3 l\u00e0 k\u1ebft qu\u1ea3 c\u1ee7a tranh \u0111\u1ea5u trong c\u1ea3 ng\u00e0y gi\u1eefa b\u00ean mua v\u00e0 b\u00ean b\u00e1n. Khi gi\u00e1 ph\u00e1 v\u1ee1 kh\u00e1ng c\u1ef1 tr\u00ean nh\u01b0ng sau \u0111\u00f3 l\u1ea1i \u0111\u00f3ng d\u01b0\u1edbi kh\u00e1ng c\u1ef1 th\u00ec c\u00f3 ngh\u0129a l\u00e0 break \u0111\u00e3 th\u1ea5t b\u1ea1i (T\u01b0\u01a1ng t\u1ef1 v\u1edbi h\u1ed7 tr\u1ee3). Nh\u01b0ng khi gi\u00e1 \u0111\u00f3ng c\u1eeda tr\u00ean kh\u00e1ng c\u1ef1 th\u1ec3 hi\u1ec7n c\u00fa break th\u00e0nh c\u00f4ng; \u0111\u00f3ng c\u00e0ng xa th\u00ec c\u00e0ng t\u1ed1t.<\/p>\n

      V\u1edbi Bollinger Band, khi gi\u00e1 ph\u00e1 v\u1ee1 bi\u00ean sau \u0111\u00f3 \u0111\u00f3ng ngo\u00e0i bi\u00ean th\u00ec c\u00f3 ngh\u0129a l\u00e0 n\u00f3 s\u1ebd ti\u1ebfp t\u1ee5c xu h\u01b0\u1edbng hi\u1ec7n h\u00e0nh. \u0110ang b\u00e1m bi\u00ean tr\u00ean th\u00ec n\u00f3 s\u1ebd ti\u1ebfp t\u1ee5c \u0111i l\u00ean v\u00e0 \u0111ang b\u00e1m bi\u00ean d\u01b0\u1edbi th\u00ec n\u00f3 ti\u1ebfp t\u1ee5c \u0111i xu\u1ed1ng. Khi gi\u00e1 \u0111\u1eadp bi\u00ean nh\u01b0ng \u0111\u00f3ng c\u1eeda \u1edf trong th\u00ec c\u00f3 th\u1ec3 l\u00e0 d\u1ea5u hi\u1ec7u \u0111\u1ea3o chi\u1ec1u, c\u1ea7n xem th\u00eam c\u00e1c ch\u1ec9 b\u00e1o kh\u00e1c \u0111\u1ec3 c\u1ee7ng c\u1ed1 cho nh\u1eadn \u0111\u1ecbnh.<\/p>\n

      \u0110\u01b0\u1eddng MA20<\/strong><\/p>\n

      \u0110\u01b0\u1eddng MA20 l\u00e0 \u0111\u01b0\u1eddng trung t\u00e2m c\u1ee7a d\u1ea3i BB. N\u00f3 gi\u00fap ch\u00fang ta x\u00e1c \u0111\u1ecbnh xu h\u01b0\u1edbng c\u1ee7a cp m\u00e0 kh\u00f4ng ph\u1ea3i l\u00e0 h\u1ed7 tr\u1ee3 hay kh\u00e1ng c\u1ef1 m\u1ea1nh (C\u00e1c d\u1ea3i v\u1edbi 1 \u0111\u1ed9 l\u1ec7ch chu\u1ea9n v\u00e0 2 \u0111\u1ed9 l\u1ec7ch chu\u1ea9n m\u1edbi quan tr\u1ecdng).<\/p>\n

      Ch\u00fang ta c\u00f3 th\u1ec3 \u0111i\u1ec1u ch\u1ec9nh th\u1eddi gian c\u1ee7a \u0111\u01b0\u1eddng trung b\u00ecnh \u0111\u1ed9ng t\u1eeb 20 th\u00e0nh 50 phi\u00ean nh\u01b0ng ph\u1ea3i \u0111i\u1ec1u ch\u1ec9nh \u0111\u1ed9 l\u1ec7ch chu\u1ea9n t\u1eeb 2 l\u00ean 2,1. T\u01b0\u01a1ng t\u1ef1 khi gi\u1ea3m \u0111i th\u00e0nh 10 phi\u00ean th\u00ec \u0111i\u1ec1u ch\u1ec9nh \u0111\u1ed9 l\u1ec7ch chu\u1ea9n t\u1eeb 2 th\u00e0nh 1,9. Ch\u00fang ta n\u00ean \u0111i\u1ec1u ch\u1ec9nh t\u1edbi khi th\u1ea5y BB l\u00fac n\u00e0y \u0111\u00e3 ph\u1ea3n \u00e1nh \u0111\u00fang qu\u00e1 kh\u1ee9.<\/p>\n

      \n

      Ngu\u1ed3n:<\/strong> D\u1ea3i Bollinger \u2014 chienluocsong.com<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

      Source: https:\/\/chienluocsong.com\/dai-bollinger\/<\/p>\n","protected":false},"author":1,"featured_media":1121,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[26],"tags":[],"class_list":["post-1120","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-chienluocsong"],"_links":{"self":[{"href":"https:\/\/blog.ngocha.biz\/index.php?rest_route=\/wp\/v2\/posts\/1120","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blog.ngocha.biz\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.ngocha.biz\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.ngocha.biz\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.ngocha.biz\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=1120"}],"version-history":[{"count":1,"href":"https:\/\/blog.ngocha.biz\/index.php?rest_route=\/wp\/v2\/posts\/1120\/revisions"}],"predecessor-version":[{"id":1447,"href":"https:\/\/blog.ngocha.biz\/index.php?rest_route=\/wp\/v2\/posts\/1120\/revisions\/1447"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/blog.ngocha.biz\/index.php?rest_route=\/wp\/v2\/media\/1121"}],"wp:attachment":[{"href":"https:\/\/blog.ngocha.biz\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=1120"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.ngocha.biz\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=1120"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.ngocha.biz\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=1120"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}