{"id":1123,"date":"2025-10-23T09:06:26","date_gmt":"2025-10-23T09:06:26","guid":{"rendered":"https:\/\/blog.ngocha.biz\/?p=1123"},"modified":"2026-05-27T18:22:34","modified_gmt":"2026-05-27T18:22:34","slug":"chi-so-suc-manh-tuong-doi-rsi","status":"publish","type":"post","link":"https:\/\/blog.ngocha.biz\/?p=1123","title":{"rendered":"Ch\u1ec9 s\u1ed1 S\u1ee9c m\u1ea1nh t\u01b0\u01a1ng \u0111\u1ed1i RSI"},"content":{"rendered":"
\n \n<\/presto-player>\n<\/figure>\n<\/p><\/div>\n

RSI l\u00e0 m\u1ed9t ch\u1ec9 s\u1ed1 dao \u0111\u1ed9ng c\u00f3 thang \u0111i\u1ec3m t\u1eeb 0 t\u1edbi 100. N\u00f3 cho bi\u1ebft t\u01b0\u01a1ng quan s\u1ee9c m\u1ea1nh gi\u00e1 (kh\u00f4ng t\u00ednh t\u1edbi kh\u1ed1i l\u01b0\u1ee3ng). \u0110\u00e2y l\u00e0 ch\u1ec9 s\u1ed1 m\u00ecnh r\u1ea5t th\u00edch v\u00ec d\u1ec5 \u00e1p d\u1ee5ng. Entry n\u00e0y ch\u00fang ta \u0111i s\u00e2u v\u00e0o c\u00e1ch t\u00ednh ch\u1ec9 s\u1ed1 \u0111\u1ec3 \u00e1p d\u1ee5ng ch\u00ednh x\u00e1c h\u01a1n.<\/p>\n

\"\"<\/figure>\n

Ph\u00eda d\u01b0\u1edbi l\u00e0 b\u1ea3ng t\u00ednh RSI c\u1ee7a CP PVS:<\/p>\n

\n
\"\"<\/figure>\n<\/div>\n

RSI m\u1eb7c \u0111\u1ecbnh \u0111\u01b0\u1ee3c t\u00ednh cho 14 ng\u00e0y v\u00ec v\u1eady t\u1edbi ng\u00e0y th\u1ee9 14 ta m\u1edbi b\u1eaft \u0111\u1ea7u t\u00ednh \u0111\u01b0\u1ee3c.<\/p>\n

C\u1ed9t “thay \u0111\u1ed5i” l\u1ea5y gi\u00e1 \u0111\u00f3ng c\u1eeda c\u1ee7a ng\u00e0y h\u00f4m nay tr\u1eeb \u0111i gi\u00e1 \u0111\u00f3ng c\u1eeda c\u1ee7a ng\u00e0y h\u00f4m tr\u01b0\u1edbc.<\/p>\n

\u0110\u1ea7u ti\u00ean ta t\u00ednh RS:<\/p>\n

RS = trung b\u00ecnh t\u0103ng\/trung b\u00ecnh gi\u1ea3m<\/p>\n

Trung b\u00ecnh t\u0103ng = (0,4+0+0,8+0,4+1)\/14= 0,1857<\/p>\n

Trung b\u00ecnh gi\u1ea3m = (0,5+0,2+),9+0,3+0,3+0,6+0,9)\/14= 0,335<\/p>\n

RS = 0,1857\/0,335 = 0,55<\/p>\n

RSI = 100 – 100\/(1+0,55) = 35,62<\/p>\n

Ta ch\u1ec9 c\u00f3 th\u1ec3 t\u00ednh g\u1ea7n \u0111\u00fang ch\u1ec9 s\u1ed1 RS c\u1ee7a ng\u00e0y th\u1ee9 15 th\u00f4ng qua RS ng\u00e0y th\u1ee9 14 v\u00e0 gi\u00e1 c\u1ee7a ng\u00e0y th\u1ee9 15 m\u00e0 kh\u00f4ng th\u1ec3 t\u00ednh ch\u00ednh x\u00e1c; bu\u1ed9c ph\u1ea3i t\u00ednh theo c\u00f4ng th\u1ee9c c\u01a1 b\u1ea3n t\u1eeb \u0111\u1ea7u. Nguy\u00ean nh\u00e2n v\u00ec khi nh\u1ea9y sang ng\u00e0y 15 th\u00ec gi\u00e1 c\u1ee7a ng\u00e0y \u0111\u1ea7u ti\u00ean trong d\u00e3y 14 phi\u00ean c\u1ee7a ng\u00e0y h\u00f4m qua \u0111\u00e3 b\u1ecb lo\u1ea1i ra.<\/p>\n

N\u1ebfu ng\u00e0y 14 ch\u00ednh l\u00e0 ng\u00e0y h\u00f4m nay th\u00ec ta s\u1ebd th\u1ea5y RSI thay \u0111\u1ed5i theo gi\u00e1 hi\u1ec7n h\u00e0nh; cho t\u1edbi k\u1ebft th\u00fac ng\u00e0y th\u00ec n\u00f3 s\u1ebd l\u1ea5y gi\u00e1 \u0111\u00f3ng c\u1eeda.<\/p>\n

N\u1ebfu thay c\u00f4ng th\u1ee9 RS = Trung b\u00ecnh t\u0103ng\/trung b\u00ecnh gi\u1ea3m v\u00e0o c\u00f4ng th\u1ee9c RSI ta s\u1ebd c\u00f3 \u0111\u01b0\u1ee3c:<\/p>\n

RSI = (100+RS-100)\/(1+RS) = RS\/(1+RS) = 100* Trung b\u00ecnh t\u0103ng\/(Trung b\u00ecnh t\u0103ng + Trung b\u00ecnh gi\u1ea3m)<\/strong><\/p>\n

Quay l\u1ea1i b\u1ea3ng ta th\u1ea5y v\u00e0o ng\u00e0y 15 gi\u00e1 gi\u1ea3m 0,5 v\u00ec v\u1eady RSI gi\u1ea3m. V\u00e0o ng\u00e0y 16 gi\u00e1 gi\u1ea3m 0,9; gi\u00e1 t\u0103ng 0,4 c\u1ee7a phi\u00ean th\u1ee9 hai b\u1ecb lo\u1ea1i ra khi\u1ebfn cho RSI gi\u1ea3m m\u1ea1nh xu\u1ed1ng 26,5. <\/p>\n

Nh\u01b0 v\u1eady khi xu\u1ea5t hi\u1ec7n m\u1ed9t phi\u00ean gi\u1ea3m b\u1eb1ng v\u1edbi phi\u00ean gi\u1ea3m c\u1ee7a ng\u00e0y \u0111\u1ea7u ti\u00ean b\u1ecb lo\u1ea1i ra th\u00ec RSI s\u1ebd \u0111i ngang. N\u1ebfu n\u00f3 xu\u1ea5t hi\u1ec7n m\u1ed9t phi\u00ean gi\u1ea3m < phi\u00ean gi\u1ea3m b\u1ecb lo\u1ea1i ra th\u00ec RSI \u0111i l\u00ean (m\u1eb7c d\u00f9 gi\u00e1 v\u1eabn gi\u1ea3m). RSI c\u00f3 th\u1ec3 v\u1ec1 0 v\u00e0 \u1edf y\u00ean \u0111\u00f3 n\u1ebfu nh\u01b0 kh\u00f4ng c\u00f3 phi\u00ean t\u0103ng n\u00e0o trong 14 phi\u00ean; ho\u1eb7c c\u00f3 th\u1ec3 l\u00ean 100 khi c\u1ea3 14 phi\u00ean \u0111\u1ec1u t\u0103ng. Ch\u00eanh l\u1ec7ch “0” kh\u00f4ng l\u00e0m thay \u0111\u1ed5i gi\u00e1 tr\u1ecb cho d\u00f9 b\u1ea1n c\u00f3 cho v\u00e0o c\u00f4ng th\u1ee9c t\u00ednh trung b\u00ecnh t\u0103ng hay trung b\u00ecnh gi\u1ea3m.<\/p>\n

V\u00ec v\u1eady vi\u1ec7c hi\u1ec3u c\u00f4ng th\u1ee9c t\u00ednh c\u00e1c ch\u1ec9 b\u00e1o r\u1ea5t quan tr\u1ecdng; n\u00f3 gi\u00fap ta hi\u1ec3u \u0111\u00fang b\u1ea3n ch\u1ea5t c\u1ee7a v\u1ea5n \u0111\u1ec1 thay v\u00ec \u0111\u01a1n gi\u1ea3n l\u00e0 RSI t\u0103ng c\u00f3 ngh\u0129a l\u00e0 cp \u0111ang m\u1ea1nh l\u00ean hay gi\u1ea3m l\u00e0 cp \u0111ang y\u1ebfu \u0111i.<\/p>\n

Bi\u00ean \u0111\u1ed9 t\u0103ng, gi\u1ea3m c\u00e0ng m\u1ea1nh th\u00ec RSI lao l\u00ean hay lao xu\u1ed1ng c\u00e0ng m\u1ea1nh v\u00ec v\u1eady ta c\u00f3 th\u1ec3 xem m\u1ee9c \u0111\u1ed9 RSI di chuy\u1ec3n \u0111\u1ec3 x\u00e1c \u0111\u1ecbnh s\u1ee9c m\u1ea1nh c\u1ee7a b\u00ean b\u00e1n ho\u1eb7c b\u00ean mua.<\/p>\n

Qu\u00e1 mua – Qu\u00e1 b\u00e1n<\/p>\n

\n
\"\"<\/figure>\n<\/div>\n

Gi\u1ed1ng nh\u01b0 c\u00e1c ch\u1ec9 b\u00e1o dao \u0111\u1ed9ng kh\u00e1c; RSI c\u00f3 v\u00f9ng qu\u00e1 mua ( > 70) v\u00e0 v\u00f9ng qu\u00e1 b\u00e1n (<30). 70 v\u00e0 30 l\u00e0 m\u1eb7c \u0111\u1ecbnh. Khi CP \u0111i v\u00e0o v\u00f9ng qu\u00e1 mua th\u00ec kh\u1ea3 n\u0103ng \u0111\u1ea3o chi\u1ec1u gi\u1ea3m cao v\u00e0 khi \u0111i v\u00e0o v\u00f9ng qu\u00e1 b\u00e1n th\u00ec kh\u1ea3 n\u0103ng \u0111\u1ea3o chi\u1ec1u t\u0103ng cao. Tuy nhi\u00ean v\u1edbi nh\u1eefng cp c\u00f3 xu h\u01b0\u1edbng t\u0103ng m\u1ea1nh (ho\u1eb7c gi\u1ea3m m\u1ea1nh) n\u00f3 c\u00f3 th\u1ec3 li\u00ean t\u1ee5c trong v\u00f9ng qu\u00e1 mua qu\u00e1 b\u00e1n r\u1ea5t l\u00e2u m\u00e0 kh\u00f4ng ch\u1ecbu quay \u0111\u1ea7u. V\u00ed d\u1ee5 nh\u01b0 cp VIX h\u00ecnh b\u00ean.<\/p>\n<\/p>\n

H\u1ed7 tr\u1ee3 v\u00e0 kh\u00e1ng c\u1ef1 c\u1ee7a RSI:<\/strong><\/p>\n

R\u1ea5t d\u1ec5 d\u00e0ng ta nh\u1eadn th\u1ea5y RSI t\u1ea1o cho n\u00f3 c\u00e1c \u0111\u01b0\u1eddng kh\u00e1ng c\u1ef1 v\u00e0 h\u1ed7 tr\u1ee3. C\u00e1c \u0111\u01b0\u1eddng bi\u00ean 30 v\u00e0 70 r\u1ea5t r\u00f5 r\u00e0ng. FPT li\u00ean t\u1ee5c quay l\u00ean khi g\u1eb7p kh\u00e1ng c\u1ef1 30 m\u1eb7c d\u00f9 gi\u00e1 li\u00ean ti\u1ebfp t\u00ecm \u0111\u00e1y m\u1edbi.<\/p>\n

\"\"<\/figure>\n

Khi gi\u00e1 v\u00e0 RSI t\u1ea1o ph\u00e2n k\u1ef3 \u00e2m th\u00ec th\u01b0\u1eddng CP s\u1ebd t\u0103ng kh\u1ea3 n\u0103ng \u0111\u1ea3o chi\u1ec1u. V\u00ed d\u1ee5 v\u1edbi FPT \u1edf tr\u00ean gi\u00e1 li\u00ean ti\u1ebfp \u0111\u00e1y sau th\u1ea5p h\u01a1n \u0111\u00e1y tr\u01b0\u1edbc nh\u01b0ng RSI l\u1ea1i kh\u00f4ng t\u1ea1o \u0111\u00e1y sau th\u1ea5p h\u01a1n \u0111\u00e1y tr\u01b0\u1edbc; d\u1ef1 ki\u1ebfn cho m\u1ed9t s\u1ef1 \u0111\u1ea3o chi\u1ec1u s\u1eafp di\u1ec5n ra.<\/p>\n

RSI c\u0169ng c\u00f3 th\u1ec3 t\u1ea1o ra \u0111\u01b0\u1eddng xu h\u01b0\u1edbng khi n\u1ed1i c\u00e1c \u0111\u1ec9nh, n\u1ed1i c\u00e1c \u0111\u00e1y c\u1ee7a n\u00f3. C\u00e1c \u0111\u01b0\u1eddng xu h\u01b0\u1edbng l\u00fac n\u00e0y s\u1ebd \u0111\u00f3ng vai tr\u00f2 nh\u01b0ng kh\u00e1ng c\u1ef1 v\u00e0 h\u1ed7 tr\u1ee3.<\/p>\n

Ph\u00e2n k\u1ef3 d\u01b0\u01a1ng v\u00e0 ph\u00e2n k\u1ef3 \u00e2m:<\/mark><\/strong><\/p>\n

Trong m\u1ed9t xu h\u01b0\u1edbng gi\u1ea3m, gi\u00e1 t\u1ea1o \u0111\u00e1y sau th\u1ea5p h\u01a1n \u0111\u00e1y<\/strong> tr\u01b0\u1edbc trong khi RSI t\u1ea1o \u0111\u00e1y sau cao h\u01a1n \u0111\u00e1y tr\u01b0\u1edbc th\u00ec \u0111\u00f3 l\u00e0 ph\u00e2n k\u1ef3 d\u01b0\u01a1ng; d\u1ef1 ki\u1ebfn cho m\u1ed9t s\u1ef1 \u0111\u1ea3o chi\u1ec1u s\u1eafp t\u1edbi.<\/p>\n

Trong m\u1ed9t xu h\u01b0\u1edbng t\u0103ng, gi\u00e1 t\u1ea1o \u0111\u1ec9nh sau cao h\u01a1n \u0111\u1ec9nh<\/strong> tr\u01b0\u1edbc trong khi RSI l\u1ea1i t\u1ea1o \u0111\u1ec9nh sau th\u1ea5p h\u01a1n \u0111\u1ec9nh tr\u01b0\u1edbc; \u0111\u00f3 l\u00e0 ph\u00e2n k\u1ef3 \u00e2m, d\u1ef1 ki\u1ebfn cho m\u1ed9t s\u1ef1 \u0111\u1ea3o chi\u1ec1u s\u1eafp t\u1edbi<\/p>\n

\"\"<\/figure>\n

Xu h\u01b0\u1edbng t\u0103ng ta quan t\u00e2m t\u1edbi \u0111\u1ec9nh v\u00e0 xu h\u01b0\u1edbng gi\u1ea3m ta quan t\u00e2m t\u1edbi \u0111\u00e1y.<\/p>\n

RSI v\u00e0 MA<\/strong>, Elliott<\/strong><\/p>\n

RSI l\u00e0 ch\u1ec9 b\u00e1o dao \u0111\u1ed9ng n\u00f3 ch\u1ec9 cho ta th\u00f4ng tin v\u1ec1 \u0111\u1ed9ng l\u1ef1c c\u1ee7a vi\u1ec7c t\u0103ng gi\u1ea3m gi\u00e1. Khi gi\u00e1 tr\u00ean 50 phe mua \u0111ang chi\u1ebfm \u01b0u th\u1ebf; khi l\u1edbn h\u01a1n 70 n\u00f3 \u0111i v\u00e0o v\u00f9ng qu\u00e1 mua th\u1ec3 hi\u1ec7n phe mua \u0111ang r\u1ea5t m\u1ea1nh (ch\u1ee9 kh\u00f4ng ph\u1ea3i qu\u00e1 mu\u1ed9n \u0111\u1ec3 mua). Khi gi\u00e1 d\u01b0\u1edbi 50 phe b\u00e1n \u0111ang chi\u1ebfm \u01b0u th\u1ebf; khi nh\u1ecf h\u01a1n 30 n\u00f3 \u0111i v\u00e0o v\u00f9ng qu\u00e1 b\u00e1n th\u1ec3 hi\u1ec7n phe b\u00e1n \u0111ang r\u1ea5t m\u1ea1nh (m\u00e0 kh\u00f4ng ph\u1ea3i qu\u00e1 mu\u1ed9n \u0111\u1ec3 b\u00e1n)<\/p>\n

Ch\u00fang ta th\u01b0\u1eddng s\u1ebd ph\u1ea3i k\u1ebft h\u1ee3p v\u1edbi m\u1ed9t ch\u1ec9 b\u00e1o xu h\u01b0\u1edbng kh\u00e1c (thay v\u00ec k\u1ebft h\u1ee3p v\u1edbi m\u1ed9t ch\u1ec9 b\u00e1o dao \u0111\u1ed9ng kh\u00e1c). MA l\u00e0 \u0111\u01a1n gi\u1ea3n nh\u1ea5t; v\u00ed d\u1ee5 d\u01b0\u1edbi l\u00e0 CTD:<\/p>\n

\"\"<\/figure>\n

MA50 lu\u00f4n l\u00e0 \u0111\u01b0\u1eddng c\u1ef1c k\u1ef3 quan tr\u1ecdng \u0111\u1ed1i v\u1edbi m\u1ed9t cp. Khi gi\u00e1 g\u1eb7p MA n\u00f3 c\u00f3 xu h\u01b0\u1edbng b\u1eadt l\u1ea1i; khi n\u00f3 xuy\u00ean qua MA th\u00ec n\u00f3 c\u0169ng c\u00f3 xu h\u01b0\u1edbng quay tr\u1edf l\u1ea1i. T\u1ea1i \u0111i\u1ec3m \u0111\u1ea3o chi\u1ec1u gi\u00e1 t\u1ea1o m\u00f4 h\u00ecnh hai \u0111\u00e1y \u0111\u00e1y sau th\u1ea5p h\u01a1n \u0111\u00e1y tr\u01b0\u1edbc; c\u00f9ng l\u00fac \u0111\u00f3 RSI t\u1ea1o ph\u00e2n k\u1ef3 d\u01b0\u01a1ng khi c\u0169ng t\u1ea1o \u0111\u00e1y sau th\u1ea5p h\u01a1n \u0111\u00e1y tr\u01b0\u1edbc.<\/p>\n

Ph\u00eda d\u01b0\u1edbi c\u0169ng l\u00e0 CTD; ta th\u1ea5y khi gi\u00e1 c\u1eaft l\u00ean MA20 v\u00e0 RSI \u0111ang t\u1eeb d\u01b0\u1edbi 50 v\u01b0\u1ee3t l\u00ean 50 th\u00ec gi\u00e1 ti\u1ebfp t\u1ee5c \u0111i l\u00ean. Khi gi\u00e1 c\u1eaft xu\u1ed1ng MA20 v\u00e0 RSI c\u0169ng c\u1eaft xu\u1ed1ng 50 th\u00ec gi\u00e1 ti\u1ebfp t\u1ee5c \u0111i xu\u00f3ng.<\/p>\n

\"\"<\/figure>\n

Ph\u00eda d\u01b0\u1edbi l\u00e0 \u0111\u1ed3 th\u1ecb k\u1ef9 thu\u1eadt c\u1ee7a HPG<\/strong><\/p>\n

\"\"<\/figure>\n

HPG \u0111\u00e3 qua 5 s\u00f3ng \u0111\u1ea9y c\u1ee7a Elliott v\u00e0 \u0111ang trong s\u00f3ng \u0111i\u1ec1u ch\u1ec9nh. RSI \u0111ang h\u01b0\u1edbng xu\u1ed1ng theo k\u00eanh song song. Hi\u1ec7n HPG g\u1eb7p h\u1ed7 tr\u1ee3 gi\u1ed1ng nh\u01b0 ch\u00e2n s\u00f3ng (4) nh\u01b0ng vi\u1ec7c n\u00f3 c\u00f3 b\u1eadt l\u00ean hay kh\u00f4ng th\u00ec kh\u00f4ng ch\u1eafc v\u00ec ho\u00e0n c\u1ea3nh \u0111\u00e3 kh\u00e1c nhau. L\u1ea7n tr\u01b0\u1edbc n\u00f3 \u0111ang \u1edf ch\u00e2n s\u00f3ng 4 v\u00e0 b\u1eaft \u0111\u1ea7u s\u00f3ng 5, RSI \u0111ang tr\u00ean 50 v\u00e0 h\u01b0\u1edbng l\u00ean; l\u1ea7n n\u00e0y n\u00f3 \u1edf trong pha \u0111i\u1ec1u ch\u1ec9nh v\u00e0 RSI \u0111ang d\u01b0\u1edbi 50, h\u01b0\u1edbng xu\u1ed1ng.<\/p>\n<\/p>\n

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Con ng\u01b0\u1eddi ch\u00fang ta khi \u0111\u1ee9ng tr\u01b0\u1edbc m\u1ed9t c\u00f4ng vi\u1ec7c n\u00e0o \u0111\u00f3 lu\u00f4n c\u00f3 xu h\u01b0\u1edbng l\u00e0m n\u00f3 hi\u1ec7u qu\u1ea3 nh\u1ea5t c\u00f3 th\u1ec3. C\u00f3 ngh\u0129a thu \u0111\u01b0\u1ee3c l\u1ee3i \u00edch nhi\u1ec1u nh\u1ea5t v\u1edbi \u00edt chi ph\u00ed nh\u1ea5t. C\u00f9ng m\u1ed9t mong mu\u1ed1n nh\u01b0ng h\u00e0nh \u0111\u1ed9ng l\u1ea1i kh\u00e1c nhau v\u00e0 k\u1ebft qu\u1ea3 th\u1ef1c t\u1ebf nh\u1eadn \u0111\u01b0\u1ee3c c\u0169ng kh\u00e1c nhau:<\/p>\n